0=2x^2+16x+32

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Solution for 0=2x^2+16x+32 equation: 



0=2x^2+16x+32

We move all terms to the left:

0-(2x^2+16x+32)=0

We add all the numbers together, and all the variables

-(2x^2+16x+32)=0

We get rid of parentheses

-2x^2-16x-32=0

a = -2; b = -16; c = -32;
Δ = b2-4ac
Δ = -162-4·(-2)·(-32)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{-4}=-4$

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